Replace the few existing uses of size_t as lvol size with uint64_t for
consistency. size_t is meant to represent the size of an object in
memory, and it may be smaller than uint64_t (e.g. on 32-bit platforms).
Change-Id: Ifed8959625e18be67e98070f7fea1f2a09e4e791
Signed-off-by: Daniel Verkamp <daniel.verkamp@intel.com>
Reviewed-on: https://review.gerrithub.io/407008
Reviewed-by: Tomasz Zawadzki <tomasz.zawadzki@intel.com>
Reviewed-by: Maciej Szwed <maciej.szwed@intel.com>
Tested-by: SPDK Automated Test System <sys_sgsw@intel.com>
Reviewed-by: Ben Walker <benjamin.walker@intel.com>
Reviewed-by: Jim Harris <james.r.harris@intel.com>
3b62b84f41