lib/bdev: fix potential mem leak in part.c
The way this is written currently, there is a (very very unlikely) chance that the first strdup fails and the second one succeeds. Just clean that up. Signed-off-by: Seth Howell <seth.howell@intel.com> Change-Id: I5ca1106c713753448a2bf988166a2d79ab9fa86d Reviewed-on: https://review.spdk.io/gerrit/c/spdk/spdk/+/3610 Community-CI: Mellanox Build Bot Reviewed-by: Changpeng Liu <changpeng.liu@intel.com> Reviewed-by: GangCao <gang.cao@intel.com> Reviewed-by: Tomasz Zawadzki <tomasz.zawadzki@intel.com> Reviewed-by: Ben Walker <benjamin.walker@intel.com> Reviewed-by: Jim Harris <james.r.harris@intel.com> Tested-by: SPDK CI Jenkins <sys_sgci@intel.com>
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@ -484,12 +484,13 @@ spdk_bdev_part_construct(struct spdk_bdev_part *part, struct spdk_bdev_part_base
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part->internal.bdev.dif_check_flags = base->bdev->dif_check_flags;
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part->internal.bdev.dif_check_flags = base->bdev->dif_check_flags;
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part->internal.bdev.name = strdup(name);
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part->internal.bdev.name = strdup(name);
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part->internal.bdev.product_name = strdup(product_name);
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if (part->internal.bdev.name == NULL) {
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if (part->internal.bdev.name == NULL) {
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SPDK_ERRLOG("Failed to allocate name for new part of bdev %s\n", spdk_bdev_get_name(base->bdev));
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SPDK_ERRLOG("Failed to allocate name for new part of bdev %s\n", spdk_bdev_get_name(base->bdev));
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return -1;
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return -1;
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} else if (part->internal.bdev.product_name == NULL) {
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}
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part->internal.bdev.product_name = strdup(product_name);
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if (part->internal.bdev.product_name == NULL) {
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free(part->internal.bdev.name);
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free(part->internal.bdev.name);
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SPDK_ERRLOG("Failed to allocate product name for new part of bdev %s\n",
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SPDK_ERRLOG("Failed to allocate product name for new part of bdev %s\n",
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spdk_bdev_get_name(base->bdev));
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spdk_bdev_get_name(base->bdev));
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