module/passthru: fix bug with queueing IO to bdev layer

The PT channel was used as a parameter for spdk_bdev_queue_io_wait()
when it should have been the underlying base bdev's channel.

Signed-off-by: paul luse <paul.e.luse@intel.com>
Change-Id: I6c4cf32016935a20eafd565e5688ffc43b1d9533
Reviewed-on: https://review.spdk.io/gerrit/c/spdk/spdk/+/790
Tested-by: SPDK CI Jenkins <sys_sgci@intel.com>
Reviewed-by: Darek Stojaczyk <dariusz.stojaczyk@intel.com>
Reviewed-by: Shuhei Matsumoto <shuhei.matsumoto.xt@hitachi.com>
Reviewed-by: Ben Walker <benjamin.walker@intel.com>
This commit is contained in:
paul luse 2020-02-11 20:02:01 +00:00 committed by Tomasz Zawadzki
parent a95a92208d
commit 7b16d58b1f

View File

@ -215,13 +215,15 @@ static void
vbdev_passthru_queue_io(struct spdk_bdev_io *bdev_io)
{
struct passthru_bdev_io *io_ctx = (struct passthru_bdev_io *)bdev_io->driver_ctx;
struct pt_io_channel *pt_ch = spdk_io_channel_get_ctx(io_ctx->ch);
int rc;
io_ctx->bdev_io_wait.bdev = bdev_io->bdev;
io_ctx->bdev_io_wait.cb_fn = vbdev_passthru_resubmit_io;
io_ctx->bdev_io_wait.cb_arg = bdev_io;
rc = spdk_bdev_queue_io_wait(bdev_io->bdev, io_ctx->ch, &io_ctx->bdev_io_wait);
/* Queue the IO using the channel of the base device. */
rc = spdk_bdev_queue_io_wait(bdev_io->bdev, pt_ch->base_ch, &io_ctx->bdev_io_wait);
if (rc != 0) {
SPDK_ERRLOG("Queue io failed in vbdev_passthru_queue_io, rc=%d.\n", rc);
spdk_bdev_io_complete(bdev_io, SPDK_BDEV_IO_STATUS_FAILED);